Double integration (x^2+y^2)
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(x−1)
2
+(y−2)
2
=3(
2
x+y−3
)
2
x
2
+1
2
−2x+y
2
+2
2
−2y=
2
3(x+y−3)
2
x
2
+1−2x+y
2
+4−2y=
2
3(x
2
+y
2
+(−3)
2
+2xy+2y(−3)+2(−3)x)
x
2
+y
2
−2x−2y+5=
2
3(x
2
+y
2
+9+2xy−6y−6x)
2
1
x
2
+
2
1
y
2
+3xy−7x−7y+
2
17
=0
Hence, this is the answer,
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