Question

double of 2 sin° theta​

Answer 1

HELLO Mate HERE IS YOUR ANSWER ➡️➡️The answer is =±√1−cosθ2

Explanation:

We need

cos2θ=1−2sin2(θ)

So,

cosθ=1−2sin2(θ2)

2sin2(θ2)=1−cosθ

sin2(θ2)=1−cosθ2

sin(θ2)=±√1−cosθ2