Question

double x=2.9,y=2.5

System.out.println(Math.min(Math.floor(x),y));

System.out.println(Math.max(Math.ceil(x),y));​

2

Answer 1

Output -

2

3

Explanation -

(1) Math.floor(x) will return the greatest integer than is less than or equal to the value of x i.e. 2.9 so result will be 2 and Math.min() will choose the smaller between 2 and 2.5 that is obviously 2.

(2) Math.ceil(x) will return the smallest integer than is greater than or equal to the value of x i.e. 2.9 so result will be 3 and Math.max() will choose the greater between 3 and 2.5 that is obviously 3.

Answer 2

Question:-

• Write the output of the following code segment.

Output:-

2.0

3.0

Steps:-

Given code,

double x=2.9, y=2.5;

System.out.println(Math.min(Math.floor(x), y)) ;

System.out.println(Math.max(Math.ceil(x), y)) ;

Now, we will calculate,

Math.min(Math.floor(x),y)

=Math.min(2.0,2.5)

=2.0

Also,

Math.max(Math.ceil(x),y)

=Math.max(3.0,2.5)

=3.0

Note:-

• Math.max() function is used to return the largest number among two numbers.
• Math.min() function is used to return the smallest number among two numbers.
• Math.floor() function is used to return the lower integer for the argument.
• Math.ceil() is used to return the higher integer for the given argument.