Question

doubt hai yar...explain karo​

Answer 1

Answer:

C option is the correct answer. For detailed solution check out the attachment.

Binding energy = mass defect ×c square

= 0.305×931.5 = 28.4

Answer 2

Answer:

28.4 MeV is the right answer.

Explanation:

solution:

here is given..

we know that 2H⁴

IN He no. of proton = 2

" " " n = 2

mass of proton (P) = 2×1.0073 u

mass of neutron(N) = 2×1.0087 u

where u is the atomic mass unit.

also we know that...

1U= 931.5 mev/c²

then total mass = mass of P + mass of N

so,

= 2(1.0073 + 1.0087)

= 4.0320 u

Now,

we know that the binding energy (BE)

BE =∆m×c²

where ∆m is themass defect

∆m= total mass - mass of nucleus

but there is no given the mass of nucleus.

now we know that the stable isotope of helium with relative atomic nucleus mass 4.002603.

now, ∆m = (4.0320- 4.002603)

∆m = 0.029397

now the binding energy

BE = 0.024397× 931.5

= 27.3833 mev

nearest of option C.

so C is the right ans.

I hope this solution may help you.