Question

dr
Ex. 7. Evaluate
2x^2+ 3x + 4​

Answer 1

$\text{The roots of the equation are \frac{-3+\sqrt{23}}{4} \; and\; \frac{-3-\sqrt{23}}{4} }$

Step-by-step explanation:

The given equation is $2x^2+3x+4=0\\ \textsf{We will first check wheater the equation has equal and real roots or not.}\\ \rm Here a=2,\ b=3\ and\ c=4.$

$\bf Quadratic\ Formula: \\ \bf \frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$\rm Putting\ values\ in\ the\ equation\\ \frac{-(3)\pm\sqrt{(3)^2-4\times 2\times 4}}{2\times 2}\\ \\ \implies \frac{-3\pm\sqrt{9-32}}{4}\\ \\ \implies \frac{-3\pm \sqrt{23}}{4}\\ \\ \implies \therefore x=\frac{-3+\sqrt{23}}{4}\qquad or\qquad \frac{-3-\sqrt{23}}{4}$