Draco
a line segment pa of length
D. 4.7cm and another line segment
of length AB
with the help of
of length 3.8 cm
a compass draw
another line I segment &2 such
corite the steps of construction.
If you answer I will mark you a brained person. Thank you
Answers
Answer:
hope it would be helpful for u
1) To divide a line segment in a given ratio.
Construction:
Draw a line segment of length 7.6 cm and divide it in the ratio 5 : 8. Measure the two parts.Steps of Construction:
1: Draw a line segment AB = 7.6 cm
2: Draw a ray AC making any acute angle with AB, as shown in the figure.
3: On ray AC, starting from A, mark 5 + 8 = 13 equal line segments: AA1,A1A2,A2A3,A3A4,A4A5,A5A6,A6A7,A7A8,A8A9,A9A10,A10A11,A11A12,A12A13
4: Join A13B
5: From A5, draw A5P∥A13B, meeting AB at P.
6: Thus, P divides AB in the ratio 5:8.
On measuring the two parts, we find AP = 2.9 cm and PB = 4.7 cm (approx).
Justification :
In ΔABA13, PA5∥BA13
therefore, ΔABA5∼ΔABA3
⇒APPB=AA5A5A13=58
⇒APPB=58
2) To construct a triangle similar to a given triangle as per given scale factor which may be less than or may be greater than 1.
Construction:
Draw a ΔABC in which BC=6 cm, AB= 5 cm, and AC= 4 cm, Draw a triangle similar to ΔABC with its sides equal to (2/3)th of the corresponding sides of ΔABC.Steps of Construction:
1: Draw a line segment BC = 6 cm
2: With B as centre and radius equal to 5 cm, draw an arc.
3: With C as centre and radius equal to 4 cm, draw an arc intersecting the previously drawn arc at A.
4: Join AB and AC, then ΔABC is the required triangle.
5: Below BC, make an acute angle CBX.
6: Along BX, mark off three points B1,B2 and B3 BB1=B1B2=B2B3
7: Join B3C
8: From B2, Draw B2D∥B3C, meeting BC at D.
9: From D, draw ED∥AC, meeting BA at E. Then,
EBD is the required triangle whose sides are (2/3)th of the corresponding sides of ΔABC
Justification :
Since DE∥CA
therefore, ΔABC∼ΔEBD
And EBAB=BDBC=DECA=23
Hence, we get the new triangle similar to the given triangle whose sides are equal to (2/3)th of the
corresponding sides of ΔABC