Draw a AABC. Mark a point O anywhere inside the triangle. Measure the length of the sides to prove: A. AO + BO > AB. B. BO + CO > BC Se
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Answer:
Step-by-step explanation:
In a triangle, sum of any two sides is greater than the third side.
In triangle OAB ,
OA+OB>AB (1)
In triangle OBC ,
OB+OC>BC (2)
In triangle OAC ,
OA+OC>AC (3)
Add (1), (2) and (3)
2(OA+OB+OC)>AB+BC+AC
⇒OA+OB+OC>
2
1
(AB+BC+AC)
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