Question

Draw a ∆ABC with given measures AB=5cm BC=6cm and AC=4cm. 4. Two crossroads of width 5m run at right angles through the centre of a rectangular park of length 60m and breadth 40m and parallel to the sides. Find the area of the crossroads. Also find the cost of constructing the roads at the rate of Rs 75 per m2
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Answer 1

Answer:

Step-by-step explanation:

width =5 m

length of first parallel road 70 m

area of first road 70×5=350 sq.m

length of second road 45 m

area of second road =45×5=225 sq.m

area of the common part of cross road with 5 m width that lies at the

center of the park 5×5 = 225 sq.m

area of roads = area of first road +area of second cross road−common area

=(350+225)−25

=575−25

=550sqm

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cost of the construction per sq.m =Rs.105

total cost =550×105=Rs 57750