Question

Draw a ∆ABC with sides 6cm, 8cm and 9 cm and then construct a triangle similar to ∆ABC
whose sides are 3/4
of the corresponding sides of ∆ABC.
(with steps of construction)
fast guyssss
please

Answer 1

The points can be different . The contents are purely original and I have spent 10 - 15 minutes writing this . I hope it's worth of Brainliest .

1. Draw BC = 9 cm.

2. Then construct the triangle with the other two sides being 6 cm and 8 cm .

3. Draw a line BD which makes a certain angle with BC .

4. Make four equal cuts on BD and join the H one with point C .

5. Then construct angle EFC' equal to angle FHC .

6. Join FC' .

7. Now construct angle BCA equal to angle BC'A'.

8. Draw A'C' .

9. A'BC' is the required triangle .

Answer 2

Answer:

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Step-by-step explanation:

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