Draw a ∆ ABC with sides BC = 6 cm , AB = 5 cm and ∠ABC = 60°, then construct a triangle whose sides are 3/4 times the corresponding sides of ∆ABC.
(Class 10 Maths Sample Question Paper)
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Given , a ∆ ABC , in which BC = 6 cm , AB = 5 cm & ∠ABC = 60°,
Steps of construction:
1. Draw a line segment AB =5 cm.
2. From point P draw ∠ABY = 60° and cut off BC =6 cm from BY.
3. Join AC. Thus ∆ABC is a given Triangle.
4. Now from a draw anyway X making an acute ∠BAX with base AB on the side opposite to the vertex A.
5. Mark 4 points B1,B2,B3,B4 on AX such that AB1 = B1B2 = B2B3 = B3B4.
6.Join B4B and from B3 draw B3M || B4B intersecting AB at M.
7. From point M, draw MN || BC intersecting AC at N. Thus , ∆AMN is the required triangle whose sides are 3/4 of the corresponding sides of ∆ABC.
HOPE THIS WILL HELP YOU....
Given , a ∆ ABC , in which BC = 6 cm , AB = 5 cm & ∠ABC = 60°,
Steps of construction:
1. Draw a line segment AB =5 cm.
2. From point P draw ∠ABY = 60° and cut off BC =6 cm from BY.
3. Join AC. Thus ∆ABC is a given Triangle.
4. Now from a draw anyway X making an acute ∠BAX with base AB on the side opposite to the vertex A.
5. Mark 4 points B1,B2,B3,B4 on AX such that AB1 = B1B2 = B2B3 = B3B4.
6.Join B4B and from B3 draw B3M || B4B intersecting AB at M.
7. From point M, draw MN || BC intersecting AC at N. Thus , ∆AMN is the required triangle whose sides are 3/4 of the corresponding sides of ∆ABC.
HOPE THIS WILL HELP YOU....
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