Question

Draw a ABCD Parallelogram 5cm​

Answer 1

Step-by-step explanation:

Question:

Draw a parallelogram ABCD in which BC = 5 cm, AB = 3 cm and angle ABC = 60°, divide it into triangles BCD and ABD by the diagonal BD.

Solution:

Steps of constructions:

• 1. Draw a line AB=3 cm.
• 2. Draw a ray BY making an acute ∠ABY=60°.
• 3. With centre B and radius 5 cm, draw an arc cutting the point C on BY.
• 4. Draw a ray AZ making an acute ∠ZAX’=60°.(BY||AZ, ∴ ∠YBX’=ZAX’=60°)
• 5. With centre A and radius 5 cm, draw an arc cutting the point D on AZ.
• 6. Join CD
• 7. Thus we obtain a parallelogram ABCD.
• 8. Join BD, the diagonal of parallelogram ABCD.
• 9.Draw a ray BX downwards making an acute ∠CBX.
• 10. Locate 4 points B1, B2, B3, B4 on BX, such that BB1=B1B2=B2B3=B3B4.
• 11. Join B4C and from B3C draw a line B4C’||B3C intersecting the extended line segment BC at C’. 12. Draw C’D’|| CD intersecting the extended line segment BD at D’. Then, ∆D’BC’ is the required triangle whose sides are 4/3 of the corresponding sides of ∆DBC.
• 13. Now draw a line segment D’A’|| DA, where A’ lies on the extended side BA.
• 14. Finally, we observe that A’BC’D’ is a parallelogram in which A’D’=6.5 cm A’B = 4 cm and ∠A’BD’= 60° divided the triangle.

$\fbox{${{Hope}\hspace{0.33em}{its}\hspace{0.33em}{help}\hspace{0.33em}{you}}$}$

${}^{ \please \: mark \: me \: brainlist \: ans.}$