Question

Draw a circle of any radius. Take a point A on the circle. Taking A as the centre, draw another circle of the same radius. Draw two more circles in such way that they pass through the centers of the previous circles​

Answer 1

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which are passing through the centres of the other circle.

Here, point A and B are the centres of these circles and these circles are intersecting each other at point C and O.

In quadrilateral ADBC,

AD=AC(Radius of circle centered at A)

BC=BD(Radius of circle centered at B)

As radius of both circles are equal, therefore, AD=AC=BC=BD

Hence, ADBC is a rhombus and i an rhombus, the diagonals bisect each other at 90° .

Hence,

AB and CD

are at right angles.

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Answer 2

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which are passing through the centres of the other circle.

Here, point A and B are the centres of these circles and these circles are intersecting each other at point C and O.

In quadrilateral ADBC,

AD=AC(Radius of circle centered at A)

BC=BD(Radius of circle centered at B)

As radius of both circles are equal, therefore, AD=AC=BC=BD

Hence, ADBC is a rhombus and i an rhombus, the diagonals bisect each other at 90° .

Hence,

AB and CD

are at right angles.