Question

Draw a circle of radius 2 cm. Draw any three chords. Construct the perpendicular bisectors of these chords and find out where they meet? ​

Answer 1

Answer:

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Answer 2

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Step-by-step explanation:

Draw the circle with O and radius 2 cm.

1. (ii) Draw any two chords \bar{AB} and \bar{CD }in this circle.

(iii) Taking A and B as centres and radius more than half AB, draw two arcs which intersect each other at E and F.

(iv) Join EF. Thus EF is the perpendicular bisector of chord \bar{CD }.

(v) Similarly draw GH the perpendicular bisector of chord \bar{CD }.

These two perpendicular bisectors meet at O, the centre of the circle.