Question

Draw a circle of radius 3.5 cm. Draw two tangents to the circle such that they include an angle of 120 degree.
plzzz don't Google it if u don't know the answer because in previous one @kuhu is also Google it and that is wrong answer​

Answer 1

Answer:

Steps of construction

Step I. Draw a circle of any convenient radius with O as centre.

Step II. Take a point A on the circumference of the circle and join OA. Draw a perpendicular to OA at point A.

Step III. Draw a radius OB, making an angle of 90° with OA.

Step IV. Draw a perpendicular to OB at point B Let both the perpendicular intersect at point P

Step V. Join OP

PA and PB are the required tangents, which make an angle of 45° with OP.....

Answer 2

Answer:

Follow the given steps to construct a pair of tangents.

Step 1: Take a point O on the plane and draw a circle of radius OA = 3.5 cm

Step 2: Draw ∠AOB = ∠AOC = 30° at O.

Step 3: Draw BX ⊥ OB and CX ⊥ OC at B and C

respectively. BX and CS intersects at X.

Here, BX and CX are two tangents to the circle inclined to each other at 120°.

Justification:

∠XOB = 30°

∠OBX = 90°

In ΔBOX,

∠XOB + ∠OBX + ∠BXO = 180°

∴ 30° + 90° + ∠BXO = 180°

⇒ ∠BXO = 180° – 120° = 60°

Similarly, ∠CXO = 60°

∴ ∠BXC = ∠BXO + ∠CXO = 60° + 60° = 120°

REFER TO THE ATTACHMENT ALSO....

HOPE IT HELPS UHHH