Question

draw a circle of radius 3.5 cm. Let M be the centre of the circle. Take a point T on the circle. Draw a diameter and any other chord through T. Measure the length of the diameter and the length of the chord. Compare the two lengths

Answer 1

Answer:

OA is the radius of circle & AB is the chord

Now draw a perpendicular line from the chord to the centre of circle

Let us say the point on the chord ’D’

Now we can see two triangles ΔOAD &ΔOBD

In these two triangles we see that OA = OB & OD is common, So by the properties of triangles AD = DB = 3 cm

Now applying pythagoras theorem in triangle OAD (because it is a right angle triangle)

AO

2

=AD

2

+OD

2

(3.5)

2

=3

2

+OD

2

OD

2

=12.25−9=3.25 cm

OD=1.80 cm

Step-by-step explanation:

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