Draw a circle of radius 3.5cm . Draw two tangents to the circle such that they include an angle of 120 degree
no irrevelent answer
and if anybody don't know the answer then don't copy from Google because don't have correct answer
so please its my request
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Answer:
Step 1: Take a point O on the plane and draw a circle of radius OA = 3.5 cm
Step 2: Draw ∠AOB = ∠AOC = 30° at O.
Step 3: Draw BX ⊥ OB and CX ⊥ OC at B and C respectively. BX and CS intersects at X.
Here, BX and CX are two tangents to the circle inclined to each other at 120°.
Justification:
∠XOB = 30°
∠OBX = 90°
In ΔBOX,
∠XOB + ∠OBX + ∠BXO = 180°
∴ 30° + 90° + ∠BXO = 180°
⇒ ∠BXO = 180° – 120° = 60°
Similarly, ∠CXO = 60°
∴ ∠BXC = ∠BXO + ∠CXO = 60° + 60° = 120°
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yes up answer is correct
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