Draw a circle of radius 3.6cm .Mark a point K on it.Draw tangent to the circle passing through point K
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10
Step-by-step explanation:
1) Draw a circle of radius OQ= 3.5cm with centre at O.
2) Draw an angle of 90
0
from point O.
3) Let ray of angle intersect the circle at R.
4) Now draw 90
0
from point Q
5) Draw 90
0
at point R.
6) These two arcs meet each other, mark the point as P
PQ and PR are the two tangents inclined at angle of 45
0
Now ∠AOB=90
0
and ∠APB=45
0
=∠AOB+∠APB=135
0
Answered by
3
Answer:Draw a circle of radius OQ= 3.5cm with centre ato
Draw an angle of 90⁰ from point OLet ray of angle intersect the circle at R Now draw 90⁰ from point Q
Draw 90⁰ at point R These two arcs meet each other ,
mark the point as P PQ and PR
are the two tangents is clined at angle of 45⁰
Now < APB =45⁰
= <AOB + <APB =135⁰
hope it is help you
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