Draw a circle of radius 3 cm. From a point 4.5 cm away from its centre, construct a pair of tangents to the circle.
Also, write the steps of construction.
Answers
Answer:
ANSWER
Given: Radius of the circle=3cm, OP=7cm.
Construction:
(i) With O as the centre draw a circle of radius 3cm.
(ii) Mark a point P at a distance of 7cm from O and join OP.
(iii) Draw the perpendicular bisector of OP. Let it meet OP at M.
(iv) With M as centre and MO as radius, draw another circle.
(v) Let the two circles intersect at T and T'.
(vi) Join PT and PT'. They are the required tangents. Length of the tangent, PT=6.3cm.
Verification:
In the right angled Δ OPT,
PT=OP2−OT2=72−32
=49−9=40
∴PT=6.3cm(approximately).
Answer:
the answer is on attachment
Step-by-step explanation:
Steps of construction :- draw a circle of radius 3cm
extend its radius to 4cm more(as 7=3+4)and name it ab
draw perpendicular bisector of ab and name the center O
by taking O as center draw a circle
from B construct the pair of tangents to the circle.
NOTE: i had made a rough figure... but thr fair construction looks like same... :) i hope it helps
