Question

Draw a circle of radius 3 cm. From a point 5 cm from the centre of the circle, draw two tangents to the circle. Measure the length of each tangent

Answer 1

Given, a circle of radius 3 cm whose Centre is O and a point P ,  5 cm away from its centre.

STEPS OF CONSTRUCTION:

1.Draw circle with O as centre and radius = 3 cm. Take a point P such  that OP= 5 cm.
2. Draw the bisector of OP which intersect OP at M.
3. Taking M as centre and MO as radius, draw a dotted circle. Let this circle cuts the given circuit A and B.
4.Join PA & PB.
5. Thus , PA & PB are the required tangents. By measurement using scale PA= PB = 4 cm.


HOPE THIS WILL HELP YOU...

Answer 2

Hey !!

Figure is attached ⬆⬆ there...

Step of construction :-

↪ Draw a circle from point ( O ) of radius 3 cm.
↪ Draw a line of 5 cm from ( O ) and name it as OP.
↪ Now, bisect then line segment OP taking an arc more than its midpoint.
↪ Name the point as ( N ) where ( L ) intersects OP.
↪ Taking ON as a radius draw a circle. Where this new circle touches the other one draw two tangents there as AP and PB.
↪ Measure of length of tangent is 4 cm

How 4 cm??

∆ OAP is right angled triangle. ... ( according to theorem tangent is perpendicular to radius )

${(op)}^{2} = {(oa)}^{2} + {(ap)}^{2} \\ \\ {(5)}^{2} = {(3)}^{2} + {(ap)}^{2} \\ \\ {(ap)}^{2} = 25 - 9 \\ \\ {(ap)}^{2} = 16 \\ \\ ap = \sqrt{16} \\ \\ ap = 4$

AP is a tangent.
so, length of tangent is 4 cm.

Thanks ^-^