Question

Draw a circle of radius 4.8 cm. Draw any two of its chords. Construct the perpendicular bisector of these chords.
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Answer 1

we follow this steps:–

1. Mark a point o as centre

2. From the center draw a line taking 4.8 cm length by using ruler and compass

3. Now keeping compass opened the same length

we keep pointed at the centre,

and draw a circle using the pencil and of the compass.

So,we required circle with centre o

and radius 4.8 cm.

4. Now,

we need to draw two chords.

Let two chords be AB and CD

we need to draw perpendicular bisectors of AB and CD

Drawing perpendicular bisector AB

we follow this steps

1. With A as centre,and radius more than half AB,

draw an arc on top and bottom of AB.

With B as centre and small radius as before,

draw an arc on top and bottom of AB

2. Where the two arcs intersect above AB is point P

and where the two arcs intersect below AB is point Q

join PQ

thus,PQ is the perpendicular bisector of AB

Now we draw perpendicular bisector CD

Drawing perpendicular bisector CD

we follow this steps

1. with C as centre,and radius more than half CD

draw an arc on top and bottom of CD.

with D as centre and same radius as before,

draw an arc on top and bottom of CD.

2. Where the two arcs intersect above CD is point R

and where the two arcs intersect below CD is point S

join RS

thus,RS is the perpendicular bisector of CD

we know that ,

Perpendicular bisectors of both chords meet at the

centre of the circle.