Math, asked by vandanabeniwal12, 5 months ago

Draw a circle of radius 4 cm. Draw any two of its chords. Construct the
perpendicular bisectors of these chords. Where do they meet? ​

Answers

Answered by nirusinghneesham
0

Answer:

) Mark any point C on the sheet. Now, by adjusting the compasses up to 4cm and by putting the pointer of compasses at point C, turn the compasses slowly to draw the circle. It is the required circle of 4cm radius.

(2) Take any two chords

AB

and

CD

in the circle.

(3) Taking A and B as centres and with radius more than half of

AB

, draw arcs on both sides of AB, intersecting each other at E, F. Join EF which is the perpendicular bisector of AB.

(4) Taking C and D as centres and with radius more than half of

CD

, draw arcs on both sides of CD, intersecting each other at G, H. Join GH which is the perpendicular bisector of CD.

Now, we will find that when EF and GH are extended, they meet at the centre of the circle i.e., point O.

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