Question

Draw a circle of radius 4 cm. Draw any two of its chords. Construct the perpendicular bisectors of these chords. Where do they meet? ​

Answer 1

Answer:

(i) Draw the circle with O and radius 4 cm.

(ii) Draw any two chords

and

in this circle.

(iii) Taking A and B as centres and radius more than half AB, draw two arcs which intersect each other at E and F.

(iv) Join EF. Thus EF is the perpendicular bisector of chord

.

(v) Similarly draw GH the perpendicular bisector of chord

.

These two perpendicular bisectors meet at O, the centre of the circle.

Answer 2

Answer:

(i) Draw the circle with O and radius 4 cm.

(ii) Draw any two chords \bar{AB} and \bar{CD }in this circle.

(iii) Taking A and B as centres and radius more than half AB, draw two arcs which intersect each other at E and F.

(iv) Join EF. Thus EF is the perpendicular bisector of chord \bar{CD }.

(v) Similarly draw GH the perpendicular bisector of chord \bar{CD }.

These two perpendicular bisectors meet at O, the centre of the circle.

Step-by-step explanation: