Question

Draw a circle of radius 5 cm. Draw a chord of length 6 cm. Construct the perpendicular bisector of the chord. Find the perpendicular distance between the centre and the chord. ​

Answer 1

Answer:

The distance between the center and the chord is 1.87 m.

Step-by-step explanation:

Given : A circle of radius 3.5 cm and construct a chord of length 6 cm in it.

To find : Measure the distance between the center and the chord and also draw the circle?

Solution :  

First we draw a circle of radius 3.5 cm marked as OA

Then we draw a chord on the circle with length 6 cm as AB.

Now, We draw a perpendicular bisector from the center of the circle to the chord which bisect the chord into equal parts by bisector theorem.

Marked the length as OC..

Now, take triangle OAC,

Apply Pythagoras theorem,

The distance between the center and the chord is 1.87 m.

Refer the attached figure below.

Answer 2

Step-by-step explanation:

Hope it is helpful to you