Question

Draw a circle of radius 5cm. Construct an equilateral triangle inside the circle.

9th standard
NO SPAM PLEASE

Answer 1

Step-by-step explanation:

Given : Equilateral ∆ABC whose each side is 5 cm in length.

Steps of construction :

(1) Draw a line segment BC = 5 cm.

(2) Taking B as center and radius 5 cm draw an arc.

(3) Taking C as center and radius 5 cm draw another arc which intersects the first arc at A.

(4) Join AB and AC. ∠ABC is an equilateral triangle.

(5) Draw the perpendicular bisectors of AC and AB which intersect each other at O. O is the circumcentre of ∆ABC. Join O to B.

(6) Taking O as center and radius equal to OA draw a circle which passes through three vertices of ∆ABC.

Answer 2

Answer:

ok mam i tell you the answer