.Draw a circle of radius 6 cm. From a point 10 cm away from its centre, construct the
pair of tangents to the circle.
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Step-by-step explanation:
Given:-
A circle of radius 6 cm. From a point 10 cm away from its centre
To find:-
Construct the pair of tangents to the circle.
Solution:-
Rough diagram:-
See the attachment
Construction:-
See the above attachment
Steps of Construction:-
- Draw a circle with the radius 6 cm of centre O.
- Take a point P 10 cm away from the centre of the circle and join O and P.
- Draw perpendicular bisectors XY of OP
- Mark intersecting point of XY to OP as M
- Draw a circle with the radius OM = MP .
- The new circle touches the first circle at A and B.
- Join P and A , P and B.
- PA and PB are the pair of tangents to the given circle and PA= PB = 8cm
- ∆AOP is congruent to ∆BOP,by Pythagoras theorem , OP^2=OA^2+AP^2
=> 10^2=6^2+AP^2
=> 100-36 = PA^2
=>PA^2=64
=> PA=√64
=> PA=8 cm
PA=PB = 8cm
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