Draw a circle of radius 6cm.From a point 10 cm away from its center, construct the pair of Tangents to the circle and measure their lengths?
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Steps of construction:
1. Firstly, we draw a circle with centre O and radius 6 cm.
2. Mark a point P at a distance of OP = 10 cm, and join OP.
3. Draw a right bisector of OP, intersecting OP at Q.
4. Now, taking Q as centre and radius OQ = PQ, draw a circle to intersect the given circle at T and T`.
5. Join PT and PT
to obtain the required tangents.
To find the length of the tangents.
We know that OT ⊥ PT and ΔOPT is the right triangle
Therefore, OT = 6 cm (radius) and PO = 10 cm.
So, in ΔOPT
PT2 = OP2 − OT2 [By Pythagoras theorem]
= (10)² − (6)²
= 100 – 36
= 64 PT = 8 cm
Therefore, the length of tangents
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