draw a circle of radius 6cmfrom a point10cm away from its centre .construct the pair of tangents to a circle
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Construct a circle with radius =6cm and centre be C
Locate a point A which is 10 cm from C
Then find the perpendicular bisector of line joining points C and A. lets say the mid point will be M.
Now draw an 'another circle with centre at M and radius =6cm(
2
CA
) and lets say this circle cuts the previous circle at
points N and Q then draw the lines AB and AN which are our external tangents.
Sinces △CSA is right angle triangle at L.S=90
o
Therefore using pythagoras theorem
(CQ)
2
+(SN)
2
=(CA)
2
(10)
2
−(6)
2
=(QN)
2
QN=8cm is the length of the tangent.
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