Question

draw a circle of radius r on 1/2 an graph paper and then on a 2mm graph paper. Estimate the area enclosed in each case by actually counters the squares. Now try out with circles of different radius. Establish the pattern if any, between the two observed values and the theoretical value. (area= πr²) ang modifications?​

Answer 1

Answer:

Area of Circle $=\pi r^{2} \text { or } \pi d^{2} / 4$ square units.

The 2 mm graph paper will give a better accurate result than the 0.5cm graph.

Step-by-step explanation:

Area of Circle $=\pi r^{2} \text { or } \pi d^{2} / 4$ square units.

A circle of radius 2 cm exists drawn utilizing both 0.5 cm graph paper and 2 mm graph paper.

To find the area utilizing a graph, we must calculate the number of squares inside the circle in each case.

For squares that are not fully inside, we utilize the subsequent rule:

1. If less than half of the square exists inside, we forget.

2. If better than half of a square exists inside, we calculate it as one.

In the first figure, an area of one square exists $0.5 \times 0.5=0.25 \mathrm{~cm}^{2}$

In the second figure, an area of one square exists $0.2 \times 0.2=0.04 \mathrm{~cm}^{2}$

Utilizing the above, we find the area of the circles in both cases.

The 2 mm graph paper will give a better accurate result than the 0.5cm graph.

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