Question

Draw a circle with centre O and radius 5 cm. Draw two radii OA and OB so that they

are inclined at an angle of 130ᵒ.At A and B construct tangents to the circle. Measure the

angle between them.
answer this​

Answer 1

Step-by-step explanation:

as we know that angle between tangent and radius is 90°

So, angle oac = 90°

angle obc = 90°

angle aob = 120° (given)

we see that aobc is a quadrilateral

so sum of all angles of quadrilateral is equal to 360°

90° + 90° + 120° + ? = 360°

? = 360° -90° - 90° - 120°

? = 60°

hence, angle between tangents is 60°

Answer 2

a

Step 1 : Draw a circle with radius of 5 cm and center " O "

Step 2 : Take any point " A " on circumference and join OA

.Step 3 : Now we draw 130° at point " O " with the help of protractor . As : ∠ AOB = 130° B lies on circumference of circle , So OA and OB are radius of our circle

Step 4 : With any radius ( Less than half of OA and center " A " draw another arc that intersect our line OA at "D " with same radius and center " D " draw another arc that intersect our previous arc at " E " And again with same radius and center " E" draw another arc that intersect our main arc at " F " . Now with same radius and take center " E " and " F " we draw arcs that intersect at " G " .

Step 5 : Now with same radius and center " B " draw another arc that intersect our line OB at "H " with same radius and center " H " draw another arc that intersect our previous arc at " I " And again with same radius and center " I" draw another arc that intersect our main arc at " J " . Now with same radius and take center " I " and " J " we draw arcs that intersect at " K " .

.Step 6 : Line AG and BK extend and meet at P .

Now we measure ∠ APB , we get

Now we measure ∠ APB , we get∠ APB = 50°