Question

draw a circle with centre Oand radius 3.5cm.locate a point Q in the plane of the circle such that the tangent drawn from Q to the circle makes a angle of 30 degrees with OQ. let OQ intersect the circle at A and tangent from Q to the circle touch the circle at P. draw the fig with the help of the above steps and answer the following
a)what will be the measure of angle APP
b) Measure OQ and state it's relation with OP​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Given : Circle Radius = 3.5 cm  ∠OQP = 60° & QP is tangent

To find :  ∠AOP  & Length of OQ   & Relation of OP with OQ

Solution:

∠OQP = 90°  as QP is tangent

∠OQP = 30° given

=> ∠AOP = 60°  ( as sum of angle of triangle = 180°)

Step 1 : Mark a point O

Step 2 : Using compass width = 3.5 cm and taking O as center , draw a circle

Step 3 : Draw a ray OX such that it intersect circle at A

Step 4 : Draw an angle of 60° at O an AO using protractor

Step 5 : angle drawn intersect circle at P

Step 6 : Draw an angle of 90° at P  on OP using  protractor / setsquare

Step 7 : Angle drawn intersect ray OX at Q

Measure OQ

OQ = 7 cm

OP = Radius = 3.5 cm

OQ = 2 * OP

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