draw a circle with radius 3cm and center at point O. draw two radii OA and OB such that angle AOB=60 Join A and B and measure the length of AB
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in triangle AOB
OA = OB = 3cm
therefore angle OBA = Angle OAB ( Angle opp to equal sides)
now angle OAB+ OBA+ AOB=180 ( Angle sum property)
OBA +OAB = 180-60
2(OAB) = 120
OAB = OBA = 60
Therefore AOB IS equilataral triangle
AB = 3cm
OA = OB = 3cm
therefore angle OBA = Angle OAB ( Angle opp to equal sides)
now angle OAB+ OBA+ AOB=180 ( Angle sum property)
OBA +OAB = 180-60
2(OAB) = 120
OAB = OBA = 60
Therefore AOB IS equilataral triangle
AB = 3cm
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