Physics, asked by Logeedout, 8 months ago

draw a circuit diagram consisting of a battery of four cells each of two volt 2 ohm resistor of 4 ohm resistor and a 6 ohm resistor a plug key and an ammeter are connected in series also collect the voltmeter across 6 ohm resistor​

Answers

Answered by FFAkashbhai1
4

Answer:

\huge\underline\bold\red{Answer}

Given:

A circuit diagram consisting of a battery of four cells each 2V, a 2 ohm, 4 ohm and 6 ohm resistor, a plug key and an ammeter all connected in series.

Also connect a voltmeter across 6 ohm resistor.

To find:

Find the current flowing in the circuit and the potential difference across 6 ohm resistor.

Solution:

Consider the attached figure while going through the following steps.

The total/equivalent resistance = R =  2 + 4 + 6 = 12 Ω

The total/equivalent voltage = V =  4 × 2 = 8 V

The current in the circuit = I = V/R = 8/12 = 2/3 A

The voltage across 6 Ω resistance = V = I × R = 2/3 × 6 = 4 V

Attachments:
Answered by Anonymous
0

The total/equivalent resistance = R =  2 + 4 + 6 = 12 Ω

The total/equivalent voltage = V =  4 × 2 = 8 V

The current in the circuit = I = V/R = 8/12 = 2/3 A

The voltage across 6 Ω resistance = V = I × R = 2/3 × 6 = 4 V

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