draw a circuit diagram of a combination of devices connected at home along with the amount of energy consumed by each device ( any 4 devices with both the diagram should be drawn and energy consumed-write in steps)?
Answers
Answer:
Devices that are connected to a circuit are connected to it in one of two ways: in series or in parallel. A series circuit forms a single pathway for the flow of current, while a parallel circuit forms separate paths or branches for the flow of current.
Answer:
The above principles and formulae can be used to analyze a series circuit and determine the values of the current at and electric potential difference across each of the resistors in a series circuit. Their use will be demonstrated by the mathematical analysis of the circuit shown below. The goal is to use the formulae to determine the equivalent resistance of the circuit (Req), the current at the battery (Itot), and the voltage drops and current for each of the three resistors.
The analysis begins by using the resistance values for the individual resistors in order to determine the equivalent resistance of the circuit.
Req = R1 + R2 + R3 = 17 Ω + 12 Ω + 11 Ω = 40 Ω
Now that the equivalent resistance is known, the current at the battery can be determined using the Ohm's law equation. In using the Ohm's law equation (ΔV = I • R) to determine the current in the circuit, it is important to use the battery voltage for ΔV and the equivalent resistance for R. The calculation is shown here:
Itot = ΔVbattery / Req = (60 V) / (40 Ω) = 1.5 amp
The 1.5 amp value for current is the current at the battery location. For a series circuit with no branching locations, the current is everywhere the same. The current at the battery location is the same as the current at each resistor location. Subsequently, the 1.5 amp is the value of I1, I2, and I3.
Ibattery = I1 = I2 = I3 = 1.5 amp
There are three values left to be determined - the voltage drops across each of the individual resistors. Ohm's law is used once more to determine the voltage drops for each resistor - it is simply the product of the current at each resistor (calculated above as 1.5 amp) and the resistance of each resistor (given in the problem statement). The calculations are shown below.
ΔV1 = I1 • R1
ΔV1 = (1.5 A) • (17 Ω)
ΔV1 = 25.5 V
ΔV2 = I2 • R2
ΔV2 = (1.5 A) • (12 Ω)
ΔV2 = 18 V
ΔV3 = I3 • R3
ΔV3 = (1.5 A) • (11 Ω)
ΔV3 = 16.5 V
As a check of the accuracy of the mathematics performed, it is wise to see if the calculated values satisfy the principle that the sum of the voltage drops for each individual resistor is equal to the voltage rating of the battery. In other words, is ΔVbattery = ΔV1 + ΔV2 + ΔV3 ?
Is ΔVbattery = ΔV1 + ΔV2 + ΔV3 ?
Is 60 V = 25.5 V + 18 V + 16.5 V ?
Is 60 V = 60 V?
Yes!!
The mathematical analysis of this series circuit involved a blend of concepts and equations. As is often the case in physics, the divorcing of concepts from equations when embarking on the solution to a physics problem is a dangerous act. Here, one must consider the concepts