draw a circuit diagram of a full wave rectifier. if the time period of input ac waveform in 0.02 seconds then what is the time period of output form
Answers
Answer:
Working:- The AC input voltage across secondary s
1
and s
2
changes polarity after each half cycle. Suppose during the first half cycle of input AC signal, the terminal s
1
is positive relative to centre tap O and s
2
is negative relative to O. then diode D
1
is forward bias and diode D
2
is reverse biased. Therefore diode D
1
conduct while diode D
2
does not.
In next half cycle,
the terminal s
1
is negative relative to centre tap O and s
2
is positive relative to O. then diode D
2
is forward bias and diode D
1
is reverse biased. Therefore diode D
2
conduct while diode D
1
does not.
The direction of current in resistance R
L
is same from A to B for both half cycles. hence for input AC signal the output current is a continuous series of unidirectional pulses.
solution
expand
If the period of the input AC waveform is 0.02 seconds, then the period of the output waveform is 0.01 seconds.
Explanation:
- A full wave rectifier is a device in which we get a DC output in both cycles.
- The circuit diagram of a full wave rectifier and the sawtooth wave figure are shown in the figure attached below.
- Here, The AC input is applied to the primary of the transformer. A bridge of 4 diodes is connected across the secondary coil and the output voltage is obtained across the Load resistance.
- Now, during the positive half cycle, point A becomes positive concerning B. Diodes D1 and D2 are forward biased and diodes D3 and D4 are reverse biased. The current flows from terminal A - D1 - R - D2 to terminal B.
- However, during the negative half cycle terminal B becomes positive concerning A. Diodes D3 and D4 are forward-biased and D1 and D2 are reverse-biased. The current flows from terminal B - D3 - R - D2 - A.
- The current flows in one direction through 'R' and hence a unidirectional pulsating DC voltage is obtained across 'R'.
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