Question

Draw a comparative scale to show 1 mile or km on primary and secondary division 1/2 mile or 1/2 km on secondary division represented by, where R.F. is 1:60,000.​

Answer 1

Step-by-step explanation:

⫷Question⫸:-

Draw a comparative scale to show 1 mile or km

on primary and secondary division 1/2 mile on

1/2 km on secondary division represented by, where R.F. is 1:60,000.

⫷Answer⫸:-

✯Solution✯:-

☯️FPS METHOD:-

R.F. = 1/ 60,000

●Step-1

Calculation for statement scale:-

According to the question, R.F. = Map distance (Numerator) ; Ground distance (Dinominator)

Now,

Assuming the Numerator in INCH, so both are considered as "Inch" unit and according to R.F. 1 inch is Numerator and 60,000 miles is Dinominator and 60,000 inch has to be

converted into "mile".

So,

1 inch in the map distance represented by =60,000 inch on the real ground.

1 inch in the map distance represented by =60,000/63360 (1mile = 63360 inch)

= 0.95 mile

So,

The statement scale 1 inch to 0.95 mile.

●Step-2

Calculations for total length of the scale:-

Suppose, we take 5 mile total scale, so the

length of the scale will be,

0.95 mile on the ground distance represented

by= 1 inch in the map.

1 mile on the ground distance represented

by= 1/0.95 in the map.

5 mile on the ground distance represented

by= 5×100/0.95 in the map.

= 5.3 inch

●Step-3

Numbers of primary division:-

Value of total length of the scale / Value of one primary division

= 5 mile/ 1 mile

= 5

●Step-4

Numbers of secondary division:-

Value of one primary division/Value of Secondary division

= 1 mile / 1/2 mile

= 2

☯️CGS METHOD:-

R.F. 1/ 60,000

●Step-1

Calculation for statement scale:-

According to the question, R.F. = Map distance (Numerator) ; Ground distance (Dinominator)

Now,

Assuming the Numerator in "centimeter," so both are considered as centimeter unit and according to R.F. unit 1 cm is Numerator and 60,000 is denominator and 60,000 cm has to be converted into "Kilometer".

So,

1cm in the map distance represented by

= 60,000 cm on the real ground.

1cm in the map distance represented by

= 60,000/100000 (1km=100000cm)on the real ground.

= 0.6 km

So,

The statement scale 1cm to 0.6 km.

●Step-2

Calculation for total length of the scale:-

Suppose we take 5 km total scale, so the length

of the scale will be,

O.6km on the ground distance represented by

= 1cm in the map.

1km on the ground distance represented by

= 1/0.6cm in the map.

5km on the ground distance represented by

= 5×10/0.6 cm in the map.

= 8.3 cm

●Step-3

Number of primary division :-

Value of total length of the scale/ Value of one primary division

= 5km/1km

= 5

●Step-4

Number Of secondary division:-

Value of one primary division/ Value of one secondary division

= 1km/1/2km

= 2

Answer 2

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●Step-1

Calculation for statement scale:

According to the question, R.F. = Map distance (Numerator); Ground distance

(Dinominator)

Now,

Assuming the Numerator in INCH, so both are considered as "Inch" unit an according to R.F. 1 inch is Numerator and 60,000 miles is Dinominator and 60,000 inch has to be

converted into "mile".

1 inch in the map distance represented by =60,000 inch on the real ground.

1 inch in the map distance represented by =60,000/63360 (1mile = 63360 inch

= 0.95 mile

So,

The statement scale 1 inch t

0.95 mile.

●Step-2

Calculations for total length of the scale:

Suppose, we take 5 mile total scale, so the

length of the scale will be,

0.95 mile on the ground distance represented

by= 1 inch in the map.

1 mile on the ground distance represented

by=1/0.95 in the map.

5 mile on the ground distance

represented by= 5x100/0.95 in the map.

= 5.3 inch

●Step-3

Numbers of primary division:

Value of total length of the scale / Value of one primary division

= 5 mile/ 1 mile

= 5

●Step-4

Numbers of secondary division:

Value of one primary division/Value of Secondary division

= 1 mile / 1/2 mile

= 2