Question

Draw a Daniel cell using Au and Ag electrodes which will generate
electricity. Explain the mechanism with cell reactions.

For a 1" order reaction, the rate constant is 5.22 x 10 min. What is the ti of the reaction? How much time the reaction will take to reduce the reactant molarity from 0.5 M to 0.25 M?

Answer 1

Answer:

the anode is the electrode where oxidation occurs; Cu loses two electrons to form Cu+2 . The cathode is the electrode where reduction occurs; Ag+(aq) gains electron to become Ag(s) . As a convenient substitution for the drawing, we use a cell diagram to show the parts of an electrochemical cell. For example above, the cell notation is:

Cu(s)|Cu2+(aq)oxidation half-reaction||Ag+(aq)|Ag(s)reduction half-reaction