Question

draw a diagonal to divide it into two triangles and compute the area of each, right?




9th page number 13 if you're not in 9th please don't reply ​

Answer 1

Answer:

Proved that  diagonal of a Rectangle divide it into two triangle congruent to each other

Step-by-step explanation:

Let say ABCD is rectangle

rectangle has all the angles = 90°

=> ∠A = ∠B = ∠C = ∠D = 90°

opposite sides of rectangle are equal

=> AB = CD

& BC = AD

let say Diagonal AC

divides rectangle ABCD in

ΔABC  & CDA

AB = CD

∠B  = ∠D = 90°

AC = AC  ( common)

BC = AD

=> ΔABC ≅ CDA

Now let say Diagonal BD

divides rectangle ABCD in

ΔBAD  & DCB

AB = CD

∠A  = ∠C = 90°

AC = AC  ( common)

AD = BC

=> ΔBAD  ≅ DCB

Hence proved diagonal of a Rectangle divide it into two triangle congruent to each other

Step-by-step explanation:

thank you