draw a diagram and apply the sign convention in the determination of the focal length of a spherical mirror of which forms a three times magnified real image of an object placed 16 cm in front of it
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Magnification = -3
u= -16
f=?
m=-v/u
-3=-v/-16
v=-3×16
= -48cm
1/f=1/u+1/v
=(-1/16)+(-1/48)
-1/16-1/48
By taking LCM,
= -3-1/48
-4/48
1/f=-1/12
f= -12
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