Question

Draw a diagram and show the application of forces and calculate the moment of force applied

Answer 1

a) about point A-->

moment of force due to force along A will be zero but moment of force of force along B = (50/100)* 10 = 5Nm

b) about point B-->

moment of force due to force along B will be zero but moment of force of force along A = (50/100)* 10 = 5Nm

c) about point O-->

moment of force due to Force A= (25/100)*10= 2.5Nm

moment of force due to force B= (25/100)*10 = 2.5Nm

both are clockwise therefore they will be added

net moment about O = 2.5+2.5= 5Nm

I think it's selina publication book of class 10 .

Thank you