Question

DRAW a distance time graph ofa car running at an average speed of 50 Km /hr.​

Answer 1

Answer:

Step-by-step explanation: substitution method: ex s —t = 3



Answer :

Given equations are

s – t = 3 …(i)

 …(ii)

From eqn (i), we get

⇒ s = 3 + t …(iii)

On substituting s = 3 + t in eqn (ii), we get





⇒ 6 + 2t + 3t = 6×6

⇒ 5t = 36 – 6



Now, putting the t = 6 in eqn (iii), we get

⇒ s = 3 + 6

⇒ s = 9

Thus, s = 9 andt = 6 is the required solution

Elimination method: 



Answer :

Given pair of linear equations is

 …(i)

And  …(ii)

On multiplying Eq. (i) by 5 and Eq. (ii) by 2 to make the coefficients of  equal, we get the equation as

 …(iii)

 …(iv)

On subtracting Eq. (iii) from Eq. (iv), we get











On putting  in Eq. (ii), we get









Hence,  and  , which is the required 

cross multiplication method: 

Answer :

The given equations are

 –  = – 2 … (1)

 +  =  … (2)

By taking LCM,

(1) becomes 9x – 10y + 12 = 0

(2) becomes 2x + 3y – 13 = 0

For cross multiplication method, we write the coefficients as



Hence, we get  =  = 

⇒  =  = 

⇒  =  = 

⇒ x =  = 2

⇒ y =  = 3

∴ (2, 3) is the solution to the given system.