Math, asked by 3458benish, 2 months ago

draw a fastt help
need help​

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Answered by sherakipuja
0

Answer:

Steps of Construction

(i) Draw BC = 7 cm.

(ii) Construct ∠YBC = 75°.

(iii) From ray BY, cut-off line segment BD = AB + BC = 13cm.

(iv) Join CD.

(v) Draw the perpendicular bisector of CD meeting BY at A.

(vi) Join AC to obtain the required triangle ABC.

Justification

Since A lies on the perpendicular bisector of CD.

∴ AC = AD

Now BD = 13 cm

⇒ BA + AD = 13 cm

⇒ BA + BC = 13cm

Hence, △ABC is the required triangle.

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