Draw a flowchart To input a number and check whether a number is buzz number or not. ( A number is said to be
buzz if it is ends with 7 or divisible by 7)
Answers
Answer:
For being a buzz number there are two conditions either of which must be true −
Number should end with digit 7 e.g. 27, 657, etc.
Number should be divisible by 7 e.g 63, 49, etc.
Input
number: 49
Output
it’s a buzz number
Explanation − since the number is divisible by 7 so it’s a buzz number
Input
number: 29
Output
it’s not a buzz number
Explanation − since the number is neither divisible by 7 nor end with digit 7 so it’s not a buzz number
Approach used in the given program is as follows
Input the number to check for the condition
Check whether the number is ending with digit 7 or divisible by 7
If the condition holds true print its a buzz number
If the condition doesn’t holds true print its not a buzz number
Algorithm
Start
Step 1→ declare function to check if a number is a buzz number of not
bool isBuzz(int num)
return (num % 10 == 7 || num % 7 == 0)
Step 2→ In main()
Declare int num = 67
IF (isBuzz(num))
Print "its a buzz Number\n"
End
Else
Print "its not a buzz Number\n"
End
Stop
Example
Live Demo
#include <cmath>
#include <iostream>
using namespace std;
// function to check if its a buzz number
bool isBuzz(int num){
return (num % 10 == 7 || num % 7 == 0);
}
int main(){
int num = 67;
if (isBuzz(num))
cout << "its a buzz Number\n";
else
cout << "its not a buzz Number\n";
}
Output
If run the above code it will generate the following output −
its a buzz Number
Step-by-step explanation:
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