Math, asked by Tanmaymondal4866, 1 day ago

draw a function of graph f(x)=X+1

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Answered by ThrishaR14
3

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Answered by Anonymous
44

\rm{\underline{\underline\color{darkblue}{Given:-}}}

  • Draw a function of graph f(x)=X+1.

\rm{\underline{\underline\color{darkblue}{Solution:-}}}

\begin{gathered}{\boxed{\boxed{\begin{array}{|c|c}\rm \rightarrow \:f(x) =x + 1 \\  \\  \bf Hence, \\  \\   \:  \rm  \hookrightarrow\fbox \red{m =  + x}  \\  \\  \rm \hookrightarrow  \fbox\red{c =  + 1}\end{array}}}}\end{gathered}

\bf\red{Learn  \: more :-}

\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\sf Trigonometry\: Table \\ \begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\boxed{\begin{array}{ |c |c|c|c|c|c|} \bf\angle A & \bf{0}^{ \circ} & \bf{30}^{ \circ} & \bf{45}^{ \circ} & \bf{60}^{ \circ} & \bf{90}^{ \circ} \\ \\ \rm sin A & 0 & \dfrac{1}{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{ \sqrt{3}}{2} &1 \\ \\ \rm cos \: A & 1 & \dfrac{ \sqrt{3} }{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{1}{2} &0 \\ \\ \rm tan A & 0 & \dfrac{1}{ \sqrt{3} }&1 & \sqrt{3} & \rm \infty \\ \\ \rm cosec A & \rm \infty & 2& \sqrt{2} & \dfrac{2}{ \sqrt{3} } &1 \\ \\ \rm sec A & 1 & \dfrac{2}{ \sqrt{3} }& \sqrt{2} & 2 & \rm \infty \\ \\ \rm cot A & \rm \infty & \sqrt{3} & 1 & \dfrac{1}{ \sqrt{3} } & 0 \end{array}}}\end{gathered}\end{gathered}\end{gathered} \end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered} \end{gathered}\end{gathered}\end{gathered}

@Shivangi

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