Question

Draw a graph 3x + 4x = 12.​

Answer 1

TO GRAPH LINES YOU HAVE TO FIND THE INTERCEPT WITH AXES MAKING CERO THE VARIABLES:

THE FIRST POINT TO GRAPH: 3Y-4X=12 TO FIND X INTERCEP WE MAKE CERO THE VARIABLE Y IN THE

EQUATION SO WE HAVE 3(0)-X=12...

0-4X=12 4X=12 WE HAVE X=-12/4=3 X=-3

THE FIRS POINT IS (3,0)

TO FIND THE OTHER POINT WE MAKE CERO THE VARIABLE X: 3Y+2(0)=12 3Y+0=12 3Y=12

3Y=12 WE HAVE Y=12/3=4 SO WE HAVE X=4 THE OTHER POINT WILL BE (4.0)

AND WE HAVE THE 2 NECESSARY

POINT TO MAKE THE LINE....

GRAPH (-3,O) AND (0,4) ON AXES "X" AND "Y"

Answer 2

Answer:

Notice that the terms are linear or constant, so this equation represents a straight line.

We can find the intersections with the

x and y

axes by setting

y or x

equal to zero, or equivalently covering up the corresponding term and solving the resultant equation.

So putting

x=0

we get:3y=12

Dividing both sides by 3

, we find:y=4

So the line intercepts the y

axis (which has equation x=0 ) at the point

(0,4 )

If we instead put y=0

then we get:4=12

and hence:

x=3

We can now draw our line through these two intercepts:

graph{(4x+3y-12)((x-3)^2+y^2-0.01)(x^2+(y-4)^2-0.01) = 0 [-9.21, 10.79, -2.28, 7.72]}