Question

DRAW A GRAPH OF TEHE FOLLOWING: 2x+5y+10=0

Answer 1

Answer:

Add 5y to both sides

2x−5y+5y=10+5y → 2x+0=10+5y

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Subtract 10 from both sides

2x−10=10−10+5y → 2x−10=0+5y

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Divide both sides by 5

2x5−105=55×x

But 55=1

y=25x−2 This is standard form of the equation

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The line crosses the y-axis ( yintercept ) when x=0

so yintercept=25(0)−2=−2

So one point is: (x,y)→(0,−2)

Mark that point on the graph

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The line crosses the x-axis ( xintercept ) at y=0

0=

Step-by-step explanation:

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Answer 2

Answer:

your answer ✌️

Step-by-step explation: