Question

•Draw a graph of the following equation:
1) x-2y+3=0
2)3х+y+1=0
3) x-y+1=0
4)3х+2y-12=0
5)3x-y+5=0
​

Answer 1

Answer:

Draw the graphs of the equations x−y+1=0 and 3x+2y−12=0. Determine the coordinates of the vertices of the triangle formed by these lines and the x-axis, and shade the triangular region.

Answer

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x−y+1=0

x−y=−1 ...(i)

3x+2y−12=0

3x+2y=12 ...(ii)

x−y=−1

y=1+x

x 0 −1

y 1 0

Plot (0,1) and (1,2) on graph and join them to get eqn (i)

For 3x+2y=12

⇒2y=12−3x

⇒r=

2

12−3x

x 0 4

y 6 0

Plot point (0,6) and (4,0) on graph and join them to get eqn (ii)

△ABC is the required triangle with coordinates of A as (2,3),B(−1,0) and C(4,0).