Math, asked by kiran46, 1 year ago

draw a graph of the polynomial p (x)=x2_4x_5 and find the zeros

Answers

Answered by hsidhu978
8
5 and -1 are zeroes................

kiran46: please solve how 5 and _1 arecorrect
hsidhu978: okay
hsidhu978: x^2-5x+1x-5=0 (x^2-5x)+(1x-5)=0 x(x-5)+1 (x-5)=0 (x-5)(x+1)=0 x-5=0 or x+1=0 x=5 or x=-1
kiran46: wonder full answer it is thank you
Answered by DelcieRiveria
0

Answer:

The zeros of the given polynomial are -1 and 5.

Step-by-step explanation:

The given polynomial is

f(x)=x^2-4x-5

f(x)=x^2-5x+x-5

f(x)=x(x-5)+1(x-5)

f(x)=(x+1)(x-5)

To find to zeros of the given polynomial equate f(x) equals to 0.

f(x)=0

(x+1)(x-5)=0

Using zero product property, equate each factor equal to 0.

x+1=0\Rightarrow x=-1

x-5=0\Rightarrow x=5

Therefore the zeros of the given polynomial are -1 and 5.

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