draw a graph y=x2-4hence x2-x-12=0
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Answer:
Solution :
Now, let us draw the graph of y = x2−4
x
-4
-3
-2
-1
0
1
2
3
4
x^2
16
9
4
1
0
1
4
9
16
-4
-4
-4
-4
-4
-4
-4
-4
-4
-4
y
12
5
0
-3
-4
-3
0
5
12
Points to be plotted :
(-4, 12) (-3, 5) (-2, 0) (-1, -3) (0, -4) (1, -3) (2, 0) (3, 5) (4, 12)
To find the x-coordinate of the vertex of the parabola, we may use the formula x = -b/2a
x = 0/2(2) = 0
By applying x = 0, we get the value of y.
y = 02 - 4
y = -4
Vertex (0, -4)
 visit pic**********
y = x2−4 ------(1)
0 = x2−x −12 ------(2)
(1) - (2)
y = x2 − 4
0 = x2−x −12
(-) (-) (+) (+)
-----------------
y = x + 8
Now let us draw a graph for the line
x
-3
-2
-1
0
1
2
3
x
-3
-2
-1
0
1
2
3
+8
+8
+8
+8
+8
+8
+8
+8
y
5
6
7
8
9
10
11
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