Question

Draw a labelled diagram of Daniel cell and Explain cell reaction.​

Answer 1

Answer:

Here your ans in attachment.

Answer 2

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(a) The labelled diagram of Daniell cell is as shown.

(b) The half-reactions of oxidation and reduction taking place on electrodes are as shown:

$\text{Reduction at cathode:}$

$= Zn(s)→Z {n}^{2 + } (aq) + 2_{e}$

$\text{Oxidation at anode: }$

$= C {u}^{2 + } (aq) + 2_{e}→Cu(s)$

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