Question

draw a labelled diagram of electrolysis of water and answer the following questions.
a:- Name the gases liberated at anode and cathode.
b:- Why is it that the volume of gas collected on one electrode is two times of that on the other?
c:- What would happen if dilute sulphuric acid is not added to water?​

Answer 1

Answer:

Sorry bro I won't be drawing the diagram.. for that pls look up at your NCERT book Or from the net

Explanation:

a) The gas at anode will be Oxygen and at cathode will be Hydrogen

b) During breakdown of water(H2O) Since there are two molecules of water and 1 molecule of oxygen so double amount of hydrogen is formed at cathode

c) Since dilute H2SO4 is an acid, it helps in the more efficient conduction of electricity..If acid is not added then our experiment might not give effective results

Thank you

Hopefully you understand it..